Electronics · Math shelf · Optional — for the curious · build 2026.09.23-1644
The law
P = I × V. Power equals current times voltage drop — measured in watts (W), the rate energy is being delivered. Every part in a circuit is converting energy at some number of watts, right now.
Energy is the stuff (measured in joules); power is how fast it moves (joules per second = watts). A part with current flowing through it and voltage dropping across it is taking energy out of the circuit at P = I × V watts — the LED turns its share into light, the resistor turns its share into heat. (Why the units multiply out so neatly is on the What's a Coulomb? sheet — it's arithmetic, not coincidence.)
| You know | You want | Use |
|---|---|---|
| current and voltage | the power | P = I × V |
| power and voltage | the current | I = P ÷ V |
| power and current | the voltage | V = P ÷ I |
The classic loop — 5 V supply, red LED (2.0 V drop), 220 Ω resistor (3.0 V drop), 14 mA everywhere:
| Part | P = I × V | Becomes |
|---|---|---|
| LED | 14 mA × 2.0 V = 28 mW | light (and a little warmth) |
| Resistor | 14 mA × 3.0 V = 42 mW | heat, on purpose |
| Supply delivers | 14 mA × 5.0 V = 70 mW | 28 + 42 ✓ — the books balance |
Notice the quiet scandal: the resistor throws away more power than the LED uses. That's the price of the simple circuit — the resistor's job is to burn off the extra push as heat, and 42 mW of heat is so little you'll never feel it.
Our resistors are rated ¼ W = 250 mW — the most heat they can shed before they cook. The classic loop's 42 mW isn't close. But watch what happens as resistance falls across the full 5 V:
| Straight across 5 V | Current (I = V ÷ R) | Power (P = I × V) | Verdict |
|---|---|---|---|
| 1 kΩ | 5 mA | 25 mW | cool |
| 220 Ω | ≈ 23 mA | ≈ 114 mW | warm, fine |
| 100 Ω | 50 mA | 250 mW | at the limit — noticeably hot |
| a bare wire (≈ 0 Ω) | everything the supply has | all of it, in the wire | this is a short — this is why shorts burn |
Smaller resistance means more current and the same voltage — power climbs fast. A short circuit is the limit of that story: huge current, all the supply's power converted to heat in a wire that was never meant to shed any.
Two shortcuts, for the very curious
Substitute Ohm's law (V = IR) into P = I × V and two more forms fall out: P = I² × R (swap V for IR) and P = V² ÷ R (swap I for V÷R). Handy when you only know two things about a resistor — engineers reach for all three without thinking.
Answers at the bottom. The currents come from V = IR — that sheet first if these feel unfair.
1. 8 mA × 3.2 V ≈ 26 mW. 2. 8 mA × 1.8 V ≈ 14 mW — this loop wastes less than the red one; the blue LED claims more of the 5 V. 3. I = 5 mA, P = 25 mW — a tenth of the rating; fine. 4. I = 0.25 ÷ 5 = 50 mA, then R = 5 ÷ 0.05 = 100 Ω — which is why nothing smaller than 220 Ω belongs across the rails.